3.617 \(\int x (a+b x)^{3/2} (c+d x)^{5/2} \, dx\)

Optimal. Leaf size=315 \[ -\frac {(7 a d+5 b c) (b c-a d)^5 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{512 b^{9/2} d^{7/2}}+\frac {\sqrt {a+b x} \sqrt {c+d x} (7 a d+5 b c) (b c-a d)^4}{512 b^4 d^3}-\frac {(a+b x)^{3/2} \sqrt {c+d x} (7 a d+5 b c) (b c-a d)^3}{768 b^4 d^2}-\frac {(a+b x)^{5/2} \sqrt {c+d x} (7 a d+5 b c) (b c-a d)^2}{192 b^4 d}-\frac {(a+b x)^{5/2} (c+d x)^{3/2} (7 a d+5 b c) (b c-a d)}{96 b^3 d}-\frac {(a+b x)^{5/2} (c+d x)^{5/2} (7 a d+5 b c)}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d} \]

[Out]

-1/96*(-a*d+b*c)*(7*a*d+5*b*c)*(b*x+a)^(5/2)*(d*x+c)^(3/2)/b^3/d-1/60*(7*a*d+5*b*c)*(b*x+a)^(5/2)*(d*x+c)^(5/2
)/b^2/d+1/6*(b*x+a)^(5/2)*(d*x+c)^(7/2)/b/d-1/512*(-a*d+b*c)^5*(7*a*d+5*b*c)*arctanh(d^(1/2)*(b*x+a)^(1/2)/b^(
1/2)/(d*x+c)^(1/2))/b^(9/2)/d^(7/2)-1/768*(-a*d+b*c)^3*(7*a*d+5*b*c)*(b*x+a)^(3/2)*(d*x+c)^(1/2)/b^4/d^2-1/192
*(-a*d+b*c)^2*(7*a*d+5*b*c)*(b*x+a)^(5/2)*(d*x+c)^(1/2)/b^4/d+1/512*(-a*d+b*c)^4*(7*a*d+5*b*c)*(b*x+a)^(1/2)*(
d*x+c)^(1/2)/b^4/d^3

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Rubi [A]  time = 0.19, antiderivative size = 315, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {80, 50, 63, 217, 206} \[ \frac {\sqrt {a+b x} \sqrt {c+d x} (7 a d+5 b c) (b c-a d)^4}{512 b^4 d^3}-\frac {(a+b x)^{3/2} \sqrt {c+d x} (7 a d+5 b c) (b c-a d)^3}{768 b^4 d^2}-\frac {(7 a d+5 b c) (b c-a d)^5 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{512 b^{9/2} d^{7/2}}-\frac {(a+b x)^{5/2} \sqrt {c+d x} (7 a d+5 b c) (b c-a d)^2}{192 b^4 d}-\frac {(a+b x)^{5/2} (c+d x)^{3/2} (7 a d+5 b c) (b c-a d)}{96 b^3 d}-\frac {(a+b x)^{5/2} (c+d x)^{5/2} (7 a d+5 b c)}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d} \]

Antiderivative was successfully verified.

[In]

Int[x*(a + b*x)^(3/2)*(c + d*x)^(5/2),x]

[Out]

((b*c - a*d)^4*(5*b*c + 7*a*d)*Sqrt[a + b*x]*Sqrt[c + d*x])/(512*b^4*d^3) - ((b*c - a*d)^3*(5*b*c + 7*a*d)*(a
+ b*x)^(3/2)*Sqrt[c + d*x])/(768*b^4*d^2) - ((b*c - a*d)^2*(5*b*c + 7*a*d)*(a + b*x)^(5/2)*Sqrt[c + d*x])/(192
*b^4*d) - ((b*c - a*d)*(5*b*c + 7*a*d)*(a + b*x)^(5/2)*(c + d*x)^(3/2))/(96*b^3*d) - ((5*b*c + 7*a*d)*(a + b*x
)^(5/2)*(c + d*x)^(5/2))/(60*b^2*d) + ((a + b*x)^(5/2)*(c + d*x)^(7/2))/(6*b*d) - ((b*c - a*d)^5*(5*b*c + 7*a*
d)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(512*b^(9/2)*d^(7/2))

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 80

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(c + d*x)
^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 2)), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rubi steps

\begin {align*} \int x (a+b x)^{3/2} (c+d x)^{5/2} \, dx &=\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {(5 b c+7 a d) \int (a+b x)^{3/2} (c+d x)^{5/2} \, dx}{12 b d}\\ &=-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {((b c-a d) (5 b c+7 a d)) \int (a+b x)^{3/2} (c+d x)^{3/2} \, dx}{24 b^2 d}\\ &=-\frac {(b c-a d) (5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d}-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {\left ((b c-a d)^2 (5 b c+7 a d)\right ) \int (a+b x)^{3/2} \sqrt {c+d x} \, dx}{64 b^3 d}\\ &=-\frac {(b c-a d)^2 (5 b c+7 a d) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d}-\frac {(b c-a d) (5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d}-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {\left ((b c-a d)^3 (5 b c+7 a d)\right ) \int \frac {(a+b x)^{3/2}}{\sqrt {c+d x}} \, dx}{384 b^4 d}\\ &=-\frac {(b c-a d)^3 (5 b c+7 a d) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^2}-\frac {(b c-a d)^2 (5 b c+7 a d) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d}-\frac {(b c-a d) (5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d}-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}+\frac {\left ((b c-a d)^4 (5 b c+7 a d)\right ) \int \frac {\sqrt {a+b x}}{\sqrt {c+d x}} \, dx}{512 b^4 d^2}\\ &=\frac {(b c-a d)^4 (5 b c+7 a d) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^3}-\frac {(b c-a d)^3 (5 b c+7 a d) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^2}-\frac {(b c-a d)^2 (5 b c+7 a d) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d}-\frac {(b c-a d) (5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d}-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {\left ((b c-a d)^5 (5 b c+7 a d)\right ) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx}{1024 b^4 d^3}\\ &=\frac {(b c-a d)^4 (5 b c+7 a d) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^3}-\frac {(b c-a d)^3 (5 b c+7 a d) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^2}-\frac {(b c-a d)^2 (5 b c+7 a d) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d}-\frac {(b c-a d) (5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d}-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {\left ((b c-a d)^5 (5 b c+7 a d)\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{512 b^5 d^3}\\ &=\frac {(b c-a d)^4 (5 b c+7 a d) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^3}-\frac {(b c-a d)^3 (5 b c+7 a d) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^2}-\frac {(b c-a d)^2 (5 b c+7 a d) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d}-\frac {(b c-a d) (5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d}-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {\left ((b c-a d)^5 (5 b c+7 a d)\right ) \operatorname {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{512 b^5 d^3}\\ &=\frac {(b c-a d)^4 (5 b c+7 a d) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^3}-\frac {(b c-a d)^3 (5 b c+7 a d) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^2}-\frac {(b c-a d)^2 (5 b c+7 a d) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d}-\frac {(b c-a d) (5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d}-\frac {(5 b c+7 a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d}+\frac {(a+b x)^{5/2} (c+d x)^{7/2}}{6 b d}-\frac {(b c-a d)^5 (5 b c+7 a d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{512 b^{9/2} d^{7/2}}\\ \end {align*}

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Mathematica [A]  time = 2.08, size = 345, normalized size = 1.10 \[ \frac {(a+b x)^{5/2} \sqrt {c+d x} \left (5 b^3 (c+d x)^3-\frac {(7 a d+5 b c) \left (8 b^6 d^3 (a+b x)^3 (b c-a d)^{3/2} \sqrt {\frac {b (c+d x)}{b c-a d}} \left (5 a^2 d^2-10 a b d (2 c+d x)+b^2 \left (31 c^2+42 c d x+16 d^2 x^2\right )\right )+5 b^6 \sqrt {d} \left (2 d^{3/2} (a+b x)^2 (b c-a d)^{9/2} \sqrt {\frac {b (c+d x)}{b c-a d}}-3 \sqrt {d} (a+b x) (b c-a d)^{11/2} \sqrt {\frac {b (c+d x)}{b c-a d}}+3 \sqrt {a+b x} (b c-a d)^6 \sinh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b c-a d}}\right )\right )\right )}{256 b^6 d^3 (a+b x)^3 (b c-a d)^{3/2} \sqrt {\frac {b (c+d x)}{b c-a d}}}\right )}{30 b^4 d} \]

Antiderivative was successfully verified.

[In]

Integrate[x*(a + b*x)^(3/2)*(c + d*x)^(5/2),x]

[Out]

((a + b*x)^(5/2)*Sqrt[c + d*x]*(5*b^3*(c + d*x)^3 - ((5*b*c + 7*a*d)*(8*b^6*d^3*(b*c - a*d)^(3/2)*(a + b*x)^3*
Sqrt[(b*(c + d*x))/(b*c - a*d)]*(5*a^2*d^2 - 10*a*b*d*(2*c + d*x) + b^2*(31*c^2 + 42*c*d*x + 16*d^2*x^2)) + 5*
b^6*Sqrt[d]*(-3*Sqrt[d]*(b*c - a*d)^(11/2)*(a + b*x)*Sqrt[(b*(c + d*x))/(b*c - a*d)] + 2*d^(3/2)*(b*c - a*d)^(
9/2)*(a + b*x)^2*Sqrt[(b*(c + d*x))/(b*c - a*d)] + 3*(b*c - a*d)^6*Sqrt[a + b*x]*ArcSinh[(Sqrt[d]*Sqrt[a + b*x
])/Sqrt[b*c - a*d]])))/(256*b^6*d^3*(b*c - a*d)^(3/2)*(a + b*x)^3*Sqrt[(b*(c + d*x))/(b*c - a*d)])))/(30*b^4*d
)

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fricas [A]  time = 1.06, size = 894, normalized size = 2.84 \[ \left [-\frac {15 \, {\left (5 \, b^{6} c^{6} - 18 \, a b^{5} c^{5} d + 15 \, a^{2} b^{4} c^{4} d^{2} + 20 \, a^{3} b^{3} c^{3} d^{3} - 45 \, a^{4} b^{2} c^{2} d^{4} + 30 \, a^{5} b c d^{5} - 7 \, a^{6} d^{6}\right )} \sqrt {b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \, {\left (2 \, b d x + b c + a d\right )} \sqrt {b d} \sqrt {b x + a} \sqrt {d x + c} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) - 4 \, {\left (1280 \, b^{6} d^{6} x^{5} + 75 \, b^{6} c^{5} d - 245 \, a b^{5} c^{4} d^{2} + 150 \, a^{2} b^{4} c^{3} d^{3} - 546 \, a^{3} b^{3} c^{2} d^{4} + 415 \, a^{4} b^{2} c d^{5} - 105 \, a^{5} b d^{6} + 128 \, {\left (25 \, b^{6} c d^{5} + 13 \, a b^{5} d^{6}\right )} x^{4} + 16 \, {\left (135 \, b^{6} c^{2} d^{4} + 278 \, a b^{5} c d^{5} + 3 \, a^{2} b^{4} d^{6}\right )} x^{3} + 8 \, {\left (5 \, b^{6} c^{3} d^{3} + 423 \, a b^{5} c^{2} d^{4} + 27 \, a^{2} b^{4} c d^{5} - 7 \, a^{3} b^{3} d^{6}\right )} x^{2} - 2 \, {\left (25 \, b^{6} c^{4} d^{2} - 80 \, a b^{5} c^{3} d^{3} - 174 \, a^{2} b^{4} c^{2} d^{4} + 136 \, a^{3} b^{3} c d^{5} - 35 \, a^{4} b^{2} d^{6}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{30720 \, b^{5} d^{4}}, \frac {15 \, {\left (5 \, b^{6} c^{6} - 18 \, a b^{5} c^{5} d + 15 \, a^{2} b^{4} c^{4} d^{2} + 20 \, a^{3} b^{3} c^{3} d^{3} - 45 \, a^{4} b^{2} c^{2} d^{4} + 30 \, a^{5} b c d^{5} - 7 \, a^{6} d^{6}\right )} \sqrt {-b d} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {-b d} \sqrt {b x + a} \sqrt {d x + c}}{2 \, {\left (b^{2} d^{2} x^{2} + a b c d + {\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) + 2 \, {\left (1280 \, b^{6} d^{6} x^{5} + 75 \, b^{6} c^{5} d - 245 \, a b^{5} c^{4} d^{2} + 150 \, a^{2} b^{4} c^{3} d^{3} - 546 \, a^{3} b^{3} c^{2} d^{4} + 415 \, a^{4} b^{2} c d^{5} - 105 \, a^{5} b d^{6} + 128 \, {\left (25 \, b^{6} c d^{5} + 13 \, a b^{5} d^{6}\right )} x^{4} + 16 \, {\left (135 \, b^{6} c^{2} d^{4} + 278 \, a b^{5} c d^{5} + 3 \, a^{2} b^{4} d^{6}\right )} x^{3} + 8 \, {\left (5 \, b^{6} c^{3} d^{3} + 423 \, a b^{5} c^{2} d^{4} + 27 \, a^{2} b^{4} c d^{5} - 7 \, a^{3} b^{3} d^{6}\right )} x^{2} - 2 \, {\left (25 \, b^{6} c^{4} d^{2} - 80 \, a b^{5} c^{3} d^{3} - 174 \, a^{2} b^{4} c^{2} d^{4} + 136 \, a^{3} b^{3} c d^{5} - 35 \, a^{4} b^{2} d^{6}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{15360 \, b^{5} d^{4}}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(3/2)*(d*x+c)^(5/2),x, algorithm="fricas")

[Out]

[-1/30720*(15*(5*b^6*c^6 - 18*a*b^5*c^5*d + 15*a^2*b^4*c^4*d^2 + 20*a^3*b^3*c^3*d^3 - 45*a^4*b^2*c^2*d^4 + 30*
a^5*b*c*d^5 - 7*a^6*d^6)*sqrt(b*d)*log(8*b^2*d^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 + 4*(2*b*d*x + b*c + a*d)
*sqrt(b*d)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(b^2*c*d + a*b*d^2)*x) - 4*(1280*b^6*d^6*x^5 + 75*b^6*c^5*d - 245*a
*b^5*c^4*d^2 + 150*a^2*b^4*c^3*d^3 - 546*a^3*b^3*c^2*d^4 + 415*a^4*b^2*c*d^5 - 105*a^5*b*d^6 + 128*(25*b^6*c*d
^5 + 13*a*b^5*d^6)*x^4 + 16*(135*b^6*c^2*d^4 + 278*a*b^5*c*d^5 + 3*a^2*b^4*d^6)*x^3 + 8*(5*b^6*c^3*d^3 + 423*a
*b^5*c^2*d^4 + 27*a^2*b^4*c*d^5 - 7*a^3*b^3*d^6)*x^2 - 2*(25*b^6*c^4*d^2 - 80*a*b^5*c^3*d^3 - 174*a^2*b^4*c^2*
d^4 + 136*a^3*b^3*c*d^5 - 35*a^4*b^2*d^6)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(b^5*d^4), 1/15360*(15*(5*b^6*c^6 -
18*a*b^5*c^5*d + 15*a^2*b^4*c^4*d^2 + 20*a^3*b^3*c^3*d^3 - 45*a^4*b^2*c^2*d^4 + 30*a^5*b*c*d^5 - 7*a^6*d^6)*sq
rt(-b*d)*arctan(1/2*(2*b*d*x + b*c + a*d)*sqrt(-b*d)*sqrt(b*x + a)*sqrt(d*x + c)/(b^2*d^2*x^2 + a*b*c*d + (b^2
*c*d + a*b*d^2)*x)) + 2*(1280*b^6*d^6*x^5 + 75*b^6*c^5*d - 245*a*b^5*c^4*d^2 + 150*a^2*b^4*c^3*d^3 - 546*a^3*b
^3*c^2*d^4 + 415*a^4*b^2*c*d^5 - 105*a^5*b*d^6 + 128*(25*b^6*c*d^5 + 13*a*b^5*d^6)*x^4 + 16*(135*b^6*c^2*d^4 +
278*a*b^5*c*d^5 + 3*a^2*b^4*d^6)*x^3 + 8*(5*b^6*c^3*d^3 + 423*a*b^5*c^2*d^4 + 27*a^2*b^4*c*d^5 - 7*a^3*b^3*d^
6)*x^2 - 2*(25*b^6*c^4*d^2 - 80*a*b^5*c^3*d^3 - 174*a^2*b^4*c^2*d^4 + 136*a^3*b^3*c*d^5 - 35*a^4*b^2*d^6)*x)*s
qrt(b*x + a)*sqrt(d*x + c))/(b^5*d^4)]

________________________________________________________________________________________

giac [B]  time = 4.78, size = 2677, normalized size = 8.50 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(3/2)*(d*x+c)^(5/2),x, algorithm="giac")

[Out]

1/7680*(40*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/b^3 + (b^12*c*d^5 - 25*
a*b^11*d^6)/(b^14*d^6)) - (5*b^13*c^2*d^4 + 14*a*b^12*c*d^5 - 163*a^2*b^11*d^6)/(b^14*d^6)) + 3*(5*b^14*c^3*d^
3 + 9*a*b^13*c^2*d^4 + 15*a^2*b^12*c*d^5 - 93*a^3*b^11*d^6)/(b^14*d^6))*sqrt(b*x + a) + 3*(5*b^4*c^4 + 4*a*b^3
*c^3*d + 6*a^2*b^2*c^2*d^2 + 20*a^3*b*c*d^3 - 35*a^4*d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x
+ a)*b*d - a*b*d)))/(sqrt(b*d)*b^2*d^3))*c^2*abs(b) + 640*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*sqrt(b*x + a)*
(2*(b*x + a)*(4*(b*x + a)/b^2 + (b^6*c*d^3 - 13*a*b^5*d^4)/(b^7*d^4)) - 3*(b^7*c^2*d^2 + 2*a*b^6*c*d^3 - 11*a^
2*b^5*d^4)/(b^7*d^4)) - 3*(b^3*c^3 + a*b^2*c^2*d + 3*a^2*b*c*d^2 - 5*a^3*d^3)*log(abs(-sqrt(b*d)*sqrt(b*x + a)
+ sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b*d^2))*a*c^2*abs(b)/b + 8*(sqrt(b^2*c + (b*x + a)*b*d - a
*b*d)*(2*(4*(b*x + a)*(6*(b*x + a)*(8*(b*x + a)/b^4 + (b^20*c*d^7 - 41*a*b^19*d^8)/(b^23*d^8)) - (7*b^21*c^2*d
^6 + 26*a*b^20*c*d^7 - 513*a^2*b^19*d^8)/(b^23*d^8)) + 5*(7*b^22*c^3*d^5 + 19*a*b^21*c^2*d^6 + 37*a^2*b^20*c*d
^7 - 447*a^3*b^19*d^8)/(b^23*d^8))*(b*x + a) - 15*(7*b^23*c^4*d^4 + 12*a*b^22*c^3*d^5 + 18*a^2*b^21*c^2*d^6 +
28*a^3*b^20*c*d^7 - 193*a^4*b^19*d^8)/(b^23*d^8))*sqrt(b*x + a) - 15*(7*b^5*c^5 + 5*a*b^4*c^4*d + 6*a^2*b^3*c^
3*d^2 + 10*a^3*b^2*c^2*d^3 + 35*a^4*b*c*d^4 - 63*a^5*d^5)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x
+ a)*b*d - a*b*d)))/(sqrt(b*d)*b^3*d^4))*c*d*abs(b) + 640*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*sqrt(b*x + a)*
(2*(b*x + a)*(4*(b*x + a)/b^2 + (b^6*c*d^3 - 13*a*b^5*d^4)/(b^7*d^4)) - 3*(b^7*c^2*d^2 + 2*a*b^6*c*d^3 - 11*a^
2*b^5*d^4)/(b^7*d^4)) - 3*(b^3*c^3 + a*b^2*c^2*d + 3*a^2*b*c*d^2 - 5*a^3*d^3)*log(abs(-sqrt(b*d)*sqrt(b*x + a)
+ sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b*d^2))*a^2*c*d*abs(b)/b^2 + 160*(sqrt(b^2*c + (b*x + a)*b
*d - a*b*d)*(2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/b^3 + (b^12*c*d^5 - 25*a*b^11*d^6)/(b^14*d^6)) - (5*b^13*c^
2*d^4 + 14*a*b^12*c*d^5 - 163*a^2*b^11*d^6)/(b^14*d^6)) + 3*(5*b^14*c^3*d^3 + 9*a*b^13*c^2*d^4 + 15*a^2*b^12*c
*d^5 - 93*a^3*b^11*d^6)/(b^14*d^6))*sqrt(b*x + a) + 3*(5*b^4*c^4 + 4*a*b^3*c^3*d + 6*a^2*b^2*c^2*d^2 + 20*a^3*
b*c*d^3 - 35*a^4*d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^2*
d^3))*a*c*d*abs(b)/b + (sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(4*(2*(b*x + a)*(8*(b*x + a)*(10*(b*x + a)/b^5
+ (b^30*c*d^9 - 61*a*b^29*d^10)/(b^34*d^10)) - 3*(3*b^31*c^2*d^8 + 14*a*b^30*c*d^9 - 417*a^2*b^29*d^10)/(b^34*
d^10)) + (21*b^32*c^3*d^7 + 77*a*b^31*c^2*d^8 + 183*a^2*b^30*c*d^9 - 3481*a^3*b^29*d^10)/(b^34*d^10))*(b*x + a
) - 5*(21*b^33*c^4*d^6 + 56*a*b^32*c^3*d^7 + 106*a^2*b^31*c^2*d^8 + 176*a^3*b^30*c*d^9 - 2279*a^4*b^29*d^10)/(
b^34*d^10))*(b*x + a) + 15*(21*b^34*c^5*d^5 + 35*a*b^33*c^4*d^6 + 50*a^2*b^32*c^3*d^7 + 70*a^3*b^31*c^2*d^8 +
105*a^4*b^30*c*d^9 - 793*a^5*b^29*d^10)/(b^34*d^10))*sqrt(b*x + a) + 15*(21*b^6*c^6 + 14*a*b^5*c^5*d + 15*a^2*
b^4*c^4*d^2 + 20*a^3*b^3*c^3*d^3 + 35*a^4*b^2*c^2*d^4 + 126*a^5*b*c*d^5 - 231*a^6*d^6)*log(abs(-sqrt(b*d)*sqrt
(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^4*d^5))*d^2*abs(b) + 40*(sqrt(b^2*c + (b*x + a)
*b*d - a*b*d)*(2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/b^3 + (b^12*c*d^5 - 25*a*b^11*d^6)/(b^14*d^6)) - (5*b^13*
c^2*d^4 + 14*a*b^12*c*d^5 - 163*a^2*b^11*d^6)/(b^14*d^6)) + 3*(5*b^14*c^3*d^3 + 9*a*b^13*c^2*d^4 + 15*a^2*b^12
*c*d^5 - 93*a^3*b^11*d^6)/(b^14*d^6))*sqrt(b*x + a) + 3*(5*b^4*c^4 + 4*a*b^3*c^3*d + 6*a^2*b^2*c^2*d^2 + 20*a^
3*b*c*d^3 - 35*a^4*d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^
2*d^3))*a^2*d^2*abs(b)/b^2 + 8*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(4*(b*x + a)*(6*(b*x + a)*(8*(b*x + a)/
b^4 + (b^20*c*d^7 - 41*a*b^19*d^8)/(b^23*d^8)) - (7*b^21*c^2*d^6 + 26*a*b^20*c*d^7 - 513*a^2*b^19*d^8)/(b^23*d
^8)) + 5*(7*b^22*c^3*d^5 + 19*a*b^21*c^2*d^6 + 37*a^2*b^20*c*d^7 - 447*a^3*b^19*d^8)/(b^23*d^8))*(b*x + a) - 1
5*(7*b^23*c^4*d^4 + 12*a*b^22*c^3*d^5 + 18*a^2*b^21*c^2*d^6 + 28*a^3*b^20*c*d^7 - 193*a^4*b^19*d^8)/(b^23*d^8)
)*sqrt(b*x + a) - 15*(7*b^5*c^5 + 5*a*b^4*c^4*d + 6*a^2*b^3*c^3*d^2 + 10*a^3*b^2*c^2*d^3 + 35*a^4*b*c*d^4 - 63
*a^5*d^5)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^3*d^4))*a*d^2*
abs(b)/b + 1920*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*b*x + 2*a + (b*c*d - 5*a*d^2)/d^2)*sqrt(b*x + a) + (b^
3*c^2 + 2*a*b^2*c*d - 3*a^2*b*d^2)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(s
qrt(b*d)*d))*a^2*c^2*abs(b)/b^3)/b

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maple [B]  time = 0.02, size = 1240, normalized size = 3.94 \[ \frac {\sqrt {b x +a}\, \sqrt {d x +c}\, \left (2560 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, b^{5} d^{5} x^{5}+3328 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a \,b^{4} d^{5} x^{4}+6400 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, b^{5} c \,d^{4} x^{4}+105 a^{6} d^{6} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )-450 a^{5} b c \,d^{5} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+675 a^{4} b^{2} c^{2} d^{4} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )-300 a^{3} b^{3} c^{3} d^{3} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )-225 a^{2} b^{4} c^{4} d^{2} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+96 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{2} b^{3} d^{5} x^{3}+270 a \,b^{5} c^{5} d \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+8896 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a \,b^{4} c \,d^{4} x^{3}-75 b^{6} c^{6} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+4320 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, b^{5} c^{2} d^{3} x^{3}-112 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{3} b^{2} d^{5} x^{2}+432 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{2} b^{3} c \,d^{4} x^{2}+6768 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a \,b^{4} c^{2} d^{3} x^{2}+80 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, b^{5} c^{3} d^{2} x^{2}+140 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{4} b \,d^{5} x -544 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{3} b^{2} c \,d^{4} x +696 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{2} b^{3} c^{2} d^{3} x +320 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a \,b^{4} c^{3} d^{2} x -100 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, b^{5} c^{4} d x -210 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{5} d^{5}+830 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{4} b c \,d^{4}-1092 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{3} b^{2} c^{2} d^{3}+300 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a^{2} b^{3} c^{3} d^{2}-490 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, a \,b^{4} c^{4} d +150 \sqrt {b d}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}\, b^{5} c^{5}\right )}{15360 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, b^{4} d^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(b*x+a)^(3/2)*(d*x+c)^(5/2),x)

[Out]

1/15360*(b*x+a)^(1/2)*(d*x+c)^(1/2)*(3328*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a*b^4*d^5*x^4+6400*(b*d)
^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*b^5*c*d^4*x^4+96*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a^2*b^3*d^
5*x^3+4320*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*b^5*c^2*d^3*x^3-112*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*
c)^(1/2)*a^3*b^2*d^5*x^2+80*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*b^5*c^3*d^2*x^2+140*(b*d)^(1/2)*(b*d*x
^2+a*d*x+b*c*x+a*c)^(1/2)*a^4*b*d^5*x-100*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*b^5*c^4*d*x+830*(b*d)^(1
/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a^4*b*c*d^4-1092*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a^3*b^2*c^2*d
^3+300*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a^2*b^3*c^3*d^2-490*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(
1/2)*a*b^4*c^4*d-450*a^5*b*c*d^5*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2))/(b*d)^
(1/2))+675*a^4*b^2*c^2*d^4*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))
-300*a^3*b^3*c^3*d^3*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))-225*a
^2*b^4*c^4*d^2*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))+270*a*b^5*c
^5*d*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))+2560*(b*d)^(1/2)*(b*d
*x^2+a*d*x+b*c*x+a*c)^(1/2)*b^5*d^5*x^5-210*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a^5*d^5+150*(b*d)^(1/2
)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*b^5*c^5+105*a^6*d^6*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2
)*(b*d)^(1/2))/(b*d)^(1/2))-75*b^6*c^6*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2))/
(b*d)^(1/2))+8896*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a*b^4*c*d^4*x^3+432*(b*d)^(1/2)*(b*d*x^2+a*d*x+b
*c*x+a*c)^(1/2)*a^2*b^3*c*d^4*x^2+6768*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a*b^4*c^2*d^3*x^2-544*(b*d)
^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a^3*b^2*c*d^4*x+696*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a^2*b^3
*c^2*d^3*x+320*(b*d)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*a*b^4*c^3*d^2*x)/b^4/d^3/(b*d*x^2+a*d*x+b*c*x+a*c)^
(1/2)/(b*d)^(1/2)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)^(3/2)*(d*x+c)^(5/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(a*d-b*c>0)', see `assume?` for
more details)Is a*d-b*c zero or nonzero?

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x\,{\left (a+b\,x\right )}^{3/2}\,{\left (c+d\,x\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a + b*x)^(3/2)*(c + d*x)^(5/2),x)

[Out]

int(x*(a + b*x)^(3/2)*(c + d*x)^(5/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x \left (a + b x\right )^{\frac {3}{2}} \left (c + d x\right )^{\frac {5}{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(b*x+a)**(3/2)*(d*x+c)**(5/2),x)

[Out]

Integral(x*(a + b*x)**(3/2)*(c + d*x)**(5/2), x)

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